重邮 信号与系统考试答案 考研必备
t
2h(t) ecos (t) sint (t)
22
t
2
(3) y'' 2y' y f' 2f
H(p)
p 2p 211
222
p 2p 1(p 1)(p 1)(p 1)
h(t) (e t te t) (t)
(4) y''' 6y'' 11y' 6y f' 2f H(
p 21
32
p 6p 11p 6(p 1)(p 2)(p 3)(p 1)(p 2)
p 2
=
h(t)=
pt
p 3p 1
pt
p 3
p 1
(
1 t1 3t
e) (t) e22
2.10 求h(k)
(1) y(k)+2y(k-1)=f(k-1)
解:H(E)=1 2E 1
1
1
h(k) ( 2)k 1 (k 1)
E 2
(2) y(k+2)+3y(k+1)+2y(k)=f(k+1)+f(k) H(E)=
E 1E 11
2
E 3E 2(E 1)(E 2)E 2
h(k) ( 2)k 1 (k 1)
(3) y(k)+y(k-1)+
1
y(k-2)=f(k) 4
E2
解: H(E)= 11
E2 E (E )2
42
h(k)=
E2
d12k 1
(E )H(E)EdE2
E
=1
2
dk 1
(E)dE
E
12
(k)
=(k+1)Ek
E
k
1 (k) (k 1)( ) (k). 2
12
(4) y(k)-4y(k-1)+8y(k-2)=f(k) 解: h(k)-4y(k-1)+8y(k-2)= (k)