10 因为6x <f x 精馏段理论板 n=5 '
160.337x x == ''
211.4120.0290.447y x =-=
2
22'
'2''0.246(1)
y x y y ==+2.475- ''
321.4120.0290.318y x =-=
3
33'
'3''0.159(1)
y
x y y ==+2.475- ''
431.43340.0330.195y x =-=
4
44''4''0.089(1)
y x y y ==+2.475- ''
541.4120.0290.097y x =-= 5
55''5''0.042(1)
y x y y ==+2.475-<w x 所以提留段理论板 n=4
全塔效率的计算(查表得各组分黏度1μ=0.269,2μ=0.277)
12(1)0.4090.269(10.409)0.2770.274m F F x x μμμ=+-=⨯+-⨯= 0.170.616lg T m E μ=-=0.170.616lg0.27452%-≈ 捷算法求理论板数
min 11/ln {ln[()()]}19.89818.8981W
D m D W
x x N x x α-=-=-=-
由公式 0.5458270.5914220.002743/Y X X =-+ min 2.92 1.46
0.3741 3.92R R X R --===+
代入 Y=0.488 由min
0.3165,102N N N N -==+
min,1111/ln {ln[()()]}1 4.92551D
F
D F
x x N x x α-=-=≈-
0.974
10.24
1.14ln[()()]1 4.44510.9740.24-=-=≈-
精馏段实际板层数