武汉大学版无机化学课后习题答案(9)

△rG m =△rG θ

m + RTln K θ=kJ ·mol 1- Ⅱ K θ=22

52.1507.0=0.111 △rG m =△rG θ

m + RTln K θ=3610.249—17782.590=—14.2kJ ·mol 1- Ⅲ K θ=22

266.176.0=0.360 △rG m =△rG θm + RTln K θ=3610.249+（—8264.670）=—4.7kJ ·mol 1- Ⅳ K θ=1

△rG m =△rG θm + RTln K θ=3610.249=3.6kJ ·mol 1-

Ⅴ K θ=22

76.0266.1=2.775 △rG m =△rG θm + RTln K θ=11.9kJ ·mol 1-

Ⅵ K θ=22

507.052.1=8.988 △rG m =△rG θm + RTln K θ=21.4kJ ·mol 1-

Ⅶ K θ=22

253.0773.1=49.111 △rG m =△rG θm + RTln K θ=35.1kJ ·mol

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