5 29解:gc 0.5
IE26
2
gic gb e
sIE 1 r 26bb T I0.5 E 0.55 mS 26 026 35
0.5IE0.5 0.5
9.6 mS 2626
goc gce 4 S Apcmax
2
gc9.62
40dB 10473
4gicgoc4 0.55 0.004
2
2
2
QL 2fi 2 465 30.1dB Apc Apcmax 1 Q Apcmax 1 Q2 f 10473 1 100 10 1228
0 00.7 IE260.5IE0.5 0.08
5 30解:gc 0.5 1.54 mS 22626 sIE
1 26rbb T I0.08
gic gb e E 0.1 mS
26 026 30
goc gce 10 S Apcmax
2gc1.542 592.9 28dB 4gicgoc4 0.1 0.01
2
2
gc GL 1.54 0.1Apc g G g 0.01 0.1 0.1 196 23dB L ic oc
5 32解:i i1 i2 i3 i4
a a
a0 a1 v0 vs a2 v0 vs a3 v0 vs a4 v0 vs
2
3
4
2
3
4
2
3
a0 a1 v0 vs a2 v0 vs a3 v0 vs a4 v0 vs
00
2
3
44
a1 v0 vs a2 v0 vs a3 v0 vs a4 v0 vs a1 v0 vs a2 v0 vs a3 v0 vs a4 v0 vs
3
8a2v0vs 16a4v0vs 16a4vs3v0
5 34解:因存在二次项,能进行混频。只要满足fn fi就会产生中频干扰;当fn f0 fi
时产生镜像干扰。由于不存在三次项,不会产生交调干扰;有二次项,可能产生互调干扰;若有强干扰信号,则能产生阻塞干扰。