b VC
2VC
b (2 1)VC (3)
由(1),得:
a
RTC(VC b)
2
(VC
1.5
2
VCb) TC
20.5
1(2VC b)
RTC
V
C
(2 1)
1.5
3
2
V
2
2C
VC(2 1)VC
2
1
.2VC (2 1)VC
RTC
. (2
4.
2)(1 2).
VC (4)
pC
RTCVC b
a
TC
0.5
VC(VC b)
TC
1.5
RTC
VC (2 1)VC
a
0.5
VCVC (2 1)VC
.4VC
2)
RTC(2
RTCTC
2)VC
0.5
(2
1
2)(1
22VC
2
RTC 1
VC 2 2(2 pCVCRTC
12 (2
2
2
2)(1 2)
2
(2
3
2
2
2)(1
3
2)
3
2.)(1
3
2
2)
3
2
(2 2)(1 2)
2 .34(2
3
2)(1
23
2)
(5)
由(5),得:
VC
2 (2
3
32
4
3
2)
RTCpC
2)(1
(6)
把式(6)代入(3),得: