中考数学复习高分冲刺
解:
5x 1 2x 5,①
x 4 3x 1②由①得x 2, ················································································································· 2分
5
由②得,x ············································································································· 4分
2
························································································ 6分 原不等式组的解集为x 2 ·
20.本小题满分8分.
解:(Ⅰ)这个反比例函数图象的另一支在第三象限. ··················································· 1分 因为这个反比例函数的图象分布在第一、第三象限, 所以m 5 0,解得m 5. ·························································································· 3分 (Ⅱ)如图,由第一象限内的点A在正比例函数y 2x的图象上,
设点A的坐标为 x0,2x0 x0 0 ,则点B的坐标为 x0,0 ,
1 S△OAB 4, x0·2x0 4,解得x0 2(负值舍去).
2
········································································
4 . · 点A的坐标为 2,又 点A在反比例函数y
m 5
的图象上, x
4
m 5
,即m 5 8. 2
8. ···················································································· 8分 x
反比例函数的解析式为y
21.本小题满分8分.
解(Ⅰ)法一:根据题意,可以画出如下的树形图:
3 2 第一个球 1
2 第二个球 3 3
从树形图可以看出,摸出两球出现的所有可能结果共有6种; 法二:根据题意,可以列出下表: 第二个球 (1,3) (2,3)
3 (1,2) (3,2)
2
(2,1) (3,1) 1
1 2 3 第一个球
从上表中可以看出,摸出两球出现的所有可能结果共有6种. ······································ 4分 (Ⅱ)设两个球号码之和等于5为事件A.
摸出的两个球号码之和等于5的结果有2种,它们是: 2,,,3 32 .
P A
21 . ············································································································· 8分 63
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