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28.(1)由题意,得△AEP∽△CGP,所以AE:EP=CG:GP.同理可得AH:HP=CF:FP.又因为∠EAH=∠GCF,∠AHP=∠CFP,∠HPE=∠FPG,∠AEP=∠CGP,所以矩形AEPH∽矩形CGPF (2)类似(1)可得矩形AEPH∽矩形CGPF (3)该四边形是平行四边形