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精品优质文档 欢迎你下载 ∵5a -3c =0, ∴a c =35,即
sin A =35
. 设a =3k ,则c =5k ,
∴b =(5k )2-(3k )2=4k .
∴sin B =b c =45
, ∴sin A +sin B =35+45=75
. 21.(1)证明:∵四边形ABCD 是平行四边形,∴AF ∥BC .
∴∠ADE =∠DEC .
又∵∠AFC =∠DEC ,
∴∠AFC =∠ADE .
∴DE ∥FC .
∴四边形DECF 是平行四边形.
(2)解:过点D 作DH ⊥BC 于点H ,如图所示.
∵四边形ABCD 是平行四边形,
∴∠BCD =∠A ,AB =CD =13.
又∵tan A =125=tan ∠DCH =DH CH
, ∴DH =12,CH =5.
∵DF =14,
∴CE =14.
∴EH =9.
∴DE =92+122=15.
∴CF =DE =15.