27.解:过点B作BF⊥CD于F,作BG⊥AD于G.
1
在Rt△BCF中,∠CBF=30°,∴CF=BC·sin30° =15.
2在Rt△ABG中,∠BAG=60°,∴BG=AB·sin60° = 203.
2∴CE=CF+FD+DE=15+203+2=17+203≈51.64≈51.6(cm)cm. 答:此时灯罩顶端C到桌面的高度CE约是51.6cm.
28. 解:(1) EF是 OAB的中位线, EF//AB,EF 而CD
1AB 2
1
AB,CD//AB 2
EF CD, OEF OCD, OFE ODC FOE DOC (2
) AC
sin OEF sin CAB
BC AC(3) AE OE OC,EF//CD AEG 同理FH
A,C
1
CD 3
EGAE11
,即EG CD CDAC33
AB CD2CD CD9
5GH CD 33
29. 解:在Rt△ABC中,BC ABtan ,
在Rt△ABD中, AD ABtan ········································································· (2分)