西南交通大学出版社郭运瑞高等数数第一章答案
(6
)x 1
1
u解 令u x
1,则
x 1 u 0 lim1u 0u 2
1(7)lim(cosx
x 0
x 2sinx)
1
1
lim1
解 lim(cosxx 0x
ln(cosx 2sinx)x 0
x 2sinx)
limx
ln(cosx 2sinx)x 0
e
e
e
lim1
x 0x
ln(1 cosx 2sinx 1)lim
cosx 2sinx 1 e
x 0x
1
x2
limcosx 1 e
x 0x
lim2sinx
x 0x e
lim2x
x 0x limx 0x
e2
ax bx cx1
(8)lim(x 03
)x
xx
x11ax bx cxlim1ax bx cx
解 lim(
a b c
x
xln(3
)x 0
3
) limx 0e
e
x 0xln(3
)
x
x
x
ax bx cx 3
lim1a b c 3
e
x 0xln(1 3
) e
lim
1x 0x
e
3limax 1 limbx 1cx 1
x 0xx 0x limx 0x
1 3 limxlnaxlnbxlnc e
x 0x
limx 0x lim
x 0x
(9)lim
sinx sina
x ax a
2sin
x ax a
x a解 limsinx sina
cos
sinx ax a
lim
x ax a 2lim
x ax alimcosx ax a2
x a
2limx ax alimcosx a
x a2
cosa