重邮 信号与系统考试答案 考研必备
1.7试证明 (t)=lim
0
( t)
2
2
.
( 2 t2)
(t)lim22
0( t)
0
lim
t 0
0 t 0
1.8 (1)f(t) sin( t ) (t) sin( ) (t)
1 11
(2) f(t) sin( t) (t ) sin( ) (t ) 0.707 (t )
4444
(3) f(t) sin( t ) '(t) sin( ) '(t) cos( ) (t)
1 1 1
(4) f(t) sin( t) '(t ) sin( ) '(t ) cos( ) (t )
44444
1.9 (1) sin(t) (t )dt sin 0.70744 sin5t
(2) (t)dt 5Sa(5t) (t)dt 5
t
(3) e 2t (t) '(t) dt 1 2e 2t
2
t 0
3
t
(4) (t t 1) ()dt (t2 t 1)|2| (t)dt 2
2
3
(5) (t2 2) (t 5)dt 0
100
(6) (t2 2) (t 5)dt (52 2) (t 5)dt 27
10
(7) sin ( 5)d sin5 (t 5)
0t
t
(8) ( 2 1) ()d ( 2 1)2 ( )d 2 (t)
21
(9) (2t2 t 5) (t )dt [2t2 t 5]
104
10
t
1
4
t
t
14
[4t 1] 0
(10)
t
(1 ) ( )d [ ( ) ( )]d (t) (t)
t
k 1
1.13: f1(k) k k ,f2(k) ( ) k 1 .
(1)f1(k) f2(k) k k (a)
k 1
k 1 .