高等数学A上册习题解答 至微分中值定理(13)

华中师范大学专用

{2.-u=

√

K,du=

xdx1

dx

x

xdx=

x2

1

=du

u+1

=arctanu+C

=arctanx2 1+C.

1

{3.-u=,K,dx=

1

du

(0.31)

1

dx

x

|u| 1

=udu

u2

1

du,0<u<1, =

1du, 1<u<0.

arccosu+C,0<u<1,=

arccosu+C, 1<u<0.

1

=|arccos|+C.

x √

(0.32)

(8)

dxx

ππ,(0.33)

<t<π.K§dx=

)µ {1(n {)-x=3sect,0<t<

13