高等数学A上册习题解答 至微分中值定理(9)

华中师范大学专用

SK4.1ؽȩ Vg 5

¦e ؽȩ:

(1) (√+1)(√x3 √

+1)dx=

[x2

x+

√

x+1]dx=x3x23 2+25x5+x+C.(2)

3x4+3x2+1=

dx

(3x2+1

x+1)dx=x3+arctanx+C.(3)

2ex

+3 dx=2ex+3ln|x|+C.

(4)

3

1+x 2 dx=3arctanx 2arcsinx+C.

(5) bxebxdx=

(beb)xdx

=

(beb)x

b+lnb

+C.

9

(0.15)

(0.16)

(0.17)

(0.18)

(0.19)

1.