上海交通大学出版
02345
r5 r4 r5
10345
r4 r3 r4
12045
r3 r2 r3
12305
r2 r1 r2
12340
021-2000
200
30 330
400
50
0按第二列展开
404 5
( 1)1 2
23452 300
r2 r1 r2
03 40004 523450 6 4 5
按第一列展开
03 40004 5
6 4 50 12 5
12 5
23 40r1 2r2 r1 23 40 6 480
4 5
04 504 5
(6)
a 100
000a 200
( 1)
3 3
a 50a 60a 90
a 10
(a 9)
a 3
00a 200a 4
0a 7a 30a 80
0a 4
(2 3) (2 3)
a 5a 6
a 7a 80
( 1)
3 3
(a 9)( 1)
a 5a 6a 1a 2a 7a 8a 3a 4
(a 9)[(a 5)(a 8) (a 6)(a 7)][(a 1)(a 4) (a 2)(a 3)] 4(a 9)
8,(1)
2
f(x)
4 33
22 2
135 20
x2 5 2
1
r2 2r1 r2r2 r1 r3r2 r1 r4x2 900
-11
20 55
2x2 900
1000
3 1x2 21
1x2 1
0x2 9
005
-1x2 1 1
按第三列展开( 1)1 3( 1) 5
5
(2)
x2 2r2 r3 r2 0
5(x2 9)(x2 1) 故解为x 3, 1.